Sebastian Korda vs Andrey Rublev Prediction: Bet on the Russian to win

In the Australian Open, American Sebastian Korda, world No. 26, will face Russian Andrey Rublev, currently No. 5 in the world rankings. The two men have met twice on the Tour before, both face-to-face encounters went to Andrey, who is listed as a notable favorite in the pairing.

Last week, Korda played three matches at the Adelaide tournament and reached the semifinals, where he lost very easily in two sets to Jiri Lehechka of the Czech Republic. In Melbourne, Korda has two wins in two matches; the American knocked out Czech Kopriva in five sets and Frenchman Gali in three. The match against Gali lasted just over two hours, with Korda winning 6:4, 6:4, 6:4, 6:4. During the game, Korda made 12 aces with four double faults, won 76% of points on the first serve and 74% on the second.

As expected, Rublev approached the match against Eubanks with maximum concentration and did not allow the American to take a set after a 5-set match against Wild in the first round. The match against Eubanks lasted an hour and 41 minutes, and the score of the match was 6:4, 6:4, 6:4. During the game, Andrei made ten aces with zero double faults, won 85% of points on first serve and 74% of points on second serve.

We believe Andrey will continue to win confidently on the courts of Melbourne. Rublev found his game and played a quality match against Eubanks, which ended in a three-set victory. In addition, Rublev has experience of confident victories over Korda. Both personal meetings between the guys ended with Rublev's victory in two games. So, in this pairing, we choose in favor of the Russian.